Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.8 - Energy in Chemical Reactions - Additional Questions and Problems - Page 249: 7.87a

Answer

There are 0.568 mole in 25.0 g of $CO_2$

Work Step by Step

1. Determine the molar mass of this compound (CO_2), and setup the conversion factors: Molar mass : $C: 12.01g $ $O: 16.00g * 2= 32.00g $ 12.01g + 32.00g = 44.01g $ \frac{1 \space mole \space (CO_2)}{ 44.01 \space g \space (CO_2)}$ and $ \frac{ 44.01 \space g \space (CO_2)}{1 \space mole \space (CO_2)}$ 2. Calculate the number of moles $(CO_2)$ $ 25.0g \times \frac{1 mole}{ 44.01g} = 0.568 mole$
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