Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.8 - Energy in Chemical Reactions - Additional Questions and Problems - Page 249: 7.85a

Answer

There are 5.87 g in 0.150 mole of $K$.

Work Step by Step

1. Determine the molar mass of this compound (K), and setup the conversion factors: $K: 39.10g$ $ \frac{1 \space mole \space (K)}{ 39.10 \space g \space (K)}$ and $ \frac{ 39.10 \space g \space (K)}{1 \space mole \space (K)}$ 2. Calculate the mass: $ 0.150 \space mole \times \frac{ 39.10 \space g}{1 \space mole} = 5.87 \space g$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.