Answer
There are $10.6$ g in 0.150 mole of $Cl_2$.
Work Step by Step
1. Determine the molar mass of this compound (Cl_2), and setup the conversion factors:
$Cl: 35.45g * 2= 70.90g $
$ \frac{1 \space mole \space (Cl_2)}{ 70.90 \space g \space (Cl_2)}$ and $ \frac{ 70.90 \space g \space (Cl_2)}{1 \space mole \space (Cl_2)}$
2. Calculate the mass:
$ 0.150 \space mole \times \frac{ 70.90 \space g}{1 \space mole} = 10.6 \space g$
