Answer
$\lim _{x\rightarrow \infty }\dfrac {2x}{x-4}=2$
Work Step by Step
$\lim _{x\rightarrow \infty }\dfrac {2x}{x-4}=\lim _{x\rightarrow \infty }\dfrac {2}{1-\dfrac {4}{x}}=\dfrac {2}{1-\dfrac {4}{\infty }}=\dfrac {2}{1-0}=2$
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