Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Review - Exercises - Page 942: 41

Answer

Divergent

Work Step by Step

As the function $cos(\frac{n\pi}{2})$ oscillates in a range of $[-1,1]$ when $n\to\infty$, the sequence $a_n=cos(\frac{n\pi}{2})$ is divergent when $n\to\infty$.
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