Answer
$\lim _{t\rightarrow -\infty }\dfrac {t^{4}}{t^{3}-1}=-\infty $
Work Step by Step
$\lim _{t\rightarrow -\infty }\dfrac {t^{4}}{t^{3}-1}=\dfrac {t^{4}/t^{3}}{\left( t^{3}-1\right) /t^{3}}=\dfrac {t}{1-\dfrac {1}{t^{3}}}=t=-\infty $
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