Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Review - Exercises - Page 942: 24

Answer

$ f’\left( 1\right) =\left( 1+1\right) ^{-2}=\dfrac {1}{4}$

Work Step by Step

$f\left( x\right) =\dfrac {x}{x+1}=\dfrac {x+1-1}{x+1}=1-\dfrac {1}{x+1}=1-\left( x+1\right) ^{-1}\Rightarrow f'\left( x\right) =0-\left( -1\right) \times \left( x+1\right) ^{-1-1}=\left( x+1\right) ^{-2}\Rightarrow$ $ f’\left( 1\right) =\left( 1+1\right) ^{-2}=\dfrac {1}{4}$
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