Answer
The limit as x approaches 3 is equal to 7.
Work Step by Step
1. So if we plugged 3 into x we get 0 in the numerator and 0 in the denominator, so we have to use another way.
2. $x^{2}$ is factorable into (x + 4) and (x-3), this factorization will allows us to cancel out the x-3 in the numerator and denominator, fixing our problem of getting 0 in the denominato.r
3. Canceling out the (x-3) terms from numerator and denominator leaves us with (x + 4).
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4. Now plug in 3 into x and you get 7.
5. As the limit approaches x to 3, it equals 7.
