Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX A - Numbers, Inequalities, and Absolute Values - A Exercises - Page A9: 7

Answer

$2-x$

Work Step by Step

Start with expression given: $|x-2|,x\lt2$. Since the expression inside is negative, we must take the negative of $x-2$: $|x-2|=-(x-2)=2-x$.
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