Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX A - Numbers, Inequalities, and Absolute Values - A Exercises - Page A9: 25

Answer

$x \lt 1~~$ or $~~x \gt 2$ The solution set is $~~(-\infty, 1)\cup (2,\infty)$

Work Step by Step

$(x-1)(x-2) \gt 0$ When $~~x=1~~$ or $~~x=2,~~$ then $~~(x-1)(x-2) = 0$ When $x \lt 1,~~$ then $~~(x-1)(x-2) \gt 0$ When $1 \lt x \lt 2,~~$ then $~~(x-1)(x-2) \lt 0$ When $x \gt 2,~~$ then $~~(x-1)(x-2) \gt 0$ Solution: $x \lt 1~~$ or $~~x \gt 2$ The solution set is $~~(-\infty, 1)\cup (2,\infty)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.