Answer
$-\sqrt{3} \lt x \lt \sqrt{3}$
The solution set is $~~(-\sqrt{3}, \sqrt{3})$
Work Step by Step
$x^2 \lt 3$
$\vert x \vert \lt \sqrt{3}$
$-\sqrt{3} \lt x \lt \sqrt{3}$
The solution set is $~~(-\sqrt{3}, \sqrt{3})$
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