## Calculus: Early Transcendentals 8th Edition

$x=2,-\frac{4}{3}$
Solve $|x+3|=|2x+1|$. $±(x+3)=(2x+1)$ It can be simplified as follows: $(x+3)=(2x+1)$ and $-(x+3)=(2x+1)$ $2x-x=3-1$ and $-x-3=2x+1$ $x=2$ and $x=-\frac{4}{3}$ Hence, $x=2, -\frac{4}{3}$