Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX A - Numbers, Inequalities, and Absolute Values - A Exercises: 40

Answer

$68≤ F≤86$

Work Step by Step

The interval on the Celsius scale corresponds to the temperature range. $20≤C≤30$ can be calculated as follows: Given: $C=\frac{5}{9}(F-32)$ $9C=5(F-32)$ We get, $F=\frac{9C}{5}+32$ Further, $20≤C≤30$ $\frac{9}{5}(20)≤ \frac{9}{5}C≤\frac{9}{5}(30)$ $36≤ \frac{9}{5}C≤54$ $36+32≤ \frac{9}{5}C+32≤54+32$ $68≤ \frac{9}{5}C+32≤86$ $68≤ F≤86$ Therefore, the interval on the Celsius scale corresponds to the temperature range $68≤ F≤86$.
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