Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises: 8

Answer

$$6-2e^x-2e^xx$$

Work Step by Step

$6x-2xe^x$ $\frac{d}{dx}[6x]-(\frac{d}{dx}[2x]*(e^x)+(2x)*\frac{d}{dx}[e^x])$ $6-(2(e^x)+(2x)(e^x))$ $6-2e^x-2xe^x$
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