Answer
$f'(x) = 6x+1$
Work Step by Step
Using Product Rule:
$f(x) = (x-1)(3x+4)$
$f'(x) = (1)(3x+4)+(x-1)(3) = 3x+4+3x-3=6x+1$
Expansion First and then Power Rule:
$f(x) = (x-1)(3x+4) = 3x^2+x-4$
$f'(x)=3(2)x^{2-1}+(1)x^{1-1}-4(0)x^{0-1} = 6x+1$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 15
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