Answer
$y' = 9t^2+34t-28$
Work Step by Step
Product Rule:
$y=(t^2+7t)(3t-4)$
$y'=(2t+7)(3t-4)+(t^2+7t)(3) = 9t^2 + 34t-28$
Expansion then Power Rule:
$y=(t^2+7t)(3t-4) = 3t^3-4t^2+21t^2-28t = 3t^3+17t^2-28t$
$y'=3(3)t^{3-1}+17(2)t^{2-1}-28(1)t^{1-1}=9t^2 + 34t-28$
