## Calculus: Early Transcendentals (2nd Edition)

$y'= 6x-2-2e^{-2x}$
$y = 3x^2-2x+e^{-2x}$ Using Power Rule and $\frac{d}{dx}e^{nx}$ = $ne^{nx}$: $y'=3(2)x^{(2-1)} - 2(1)x^{(1-1)}+(-2)e^{-2x} = 6x-2-2e^{-2x}$