Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 48

Answer

$f'(x) = e^{-x}(2x-3)$

Work Step by Step

$f(x) = (1-2x)(e^{-x})$ Using Product Rule: $f'(x) = (-2)(e^{-x}) + (1-2x)(-e^{-x}) = e^{-x}(2x-3)$
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