Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises: 29

Answer

$f'(w) = 2w$

Work Step by Step

Quotient Rule: $f(w) = \frac{w^3-w}{w}$ $f'(w) = \frac{(3w^2-1)(w)-(w^3-w)(1)}{w^2} = 2w$ Division Then Power Rule: $f(w) = \frac{w^3-w}{w} = w^2-1$ $f'(w) = 1(2)w^{2-1}-1(0)w^{0-1} = 2w$
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