Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 160: 7

Answer

$$36x^5-12x^3$$

Work Step by Step

$f(x)=3x^4(2x^2-1)$ $\frac{d}{dx}[3x^4]\times(2x^2-1) +(3x^4)\times \frac{d}{dx}2x^2-1$ $12x^3(2x^2-1)+3x^4(4x)$ $24x^5-12x^3+12x^5$ $36x^5-12x^3$
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