Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises: 6

Answer

$f'(x)=3x^{2}-6x+4$

Work Step by Step

Original Function $f(x)=(x-3)(x^{2}+4)$ Apply the product rule: $f(x)g'(x)+g(x)f'(x)$ $f'(x)=(x-3)(2x)+(x^{2}+4)(1)$ Distributed $f'(x)=2x^{2}-6x+x^{2}+4$ Simply and you get the answer $f'(x)=3x^{2}-6x+4$
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