## Intermediate Algebra (6th Edition)

$\sqrt[4] (x-4)^{3}$
We know that $a^{\frac{m}{n}}=\sqrt[n] (a^{m})$ (where m and n are positive integers greater than 1 with $\frac{m}{n}$ in simplest form and $\sqrt[n] a$ is a real number). Therefore, $(x-4)^{\frac{3}{4}}=\sqrt[4] (x-4)^{3}$.