Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 424: 38

Answer

$n^{8/9}$

Work Step by Step

Since $x^{-a}=\dfrac{1}{x^a}$, then, \begin{align*} \dfrac{1}{n^{-8/9}} \\\\= n^{8/9} .\end{align*}
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