Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 424: 53

Answer

$\dfrac{1}{x^{2}}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \dfrac{(x^3)^{1/2}}{x^{7/2}} \\\\= \dfrac{x^{3\cdot\frac{1}{2}}}{x^{\frac{7}{2}}} \\\\= \dfrac{x^{\frac{3}{2}}}{x^{\frac{7}{2}}} \\\\= x^{\frac{3}{2}-\frac{7}{2}} \\\\= x^{-\frac{4}{2}} \\\\= x^{-2} \\\\= \dfrac{1}{x^{2}} .\end{array}
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