Answer
$b^{\frac{17}{5}}$
Work Step by Step
Using laws of exponents, then,
\begin{align*}
b^{9/5}b^{8/5}
\\\\=
b^{\frac{9}{5}+\frac{8}{5}}
\\\\=
b^{\frac{17}{5}}
.\end{align*}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 424: 42
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