Answer
$x$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
x^{-2/5}\cdot x^{7/5}
\\\\=
x^{-\frac{2}{5}+\frac{7}{5}}
\\\\=
x^{\frac{5}{5}}
\\\\=
x
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 424: 43
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