Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set: 5

Answer

$\frac{1}{2}$

Work Step by Step

$(\frac{1}{16})^{\frac{1}{4}}=\sqrt[4] (\frac{1}{16})=\frac{1}{2}$ We know this because $(\frac{1}{2})^{4}=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}=\frac{1}{16}$
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