## Intermediate Algebra (6th Edition)

$2(\sqrt[5] (x)^{3})$
We know that $a^{\frac{m}{n}}=\sqrt[n] (a^{m})$ (where m and n are positive integers greater than 1 with $\frac{m}{n}$ in simplest form and $\sqrt[n] a$ is a real number). Therefore, $2x^{\frac{3}{5}}=2(\sqrt[5] (x)^{3})$. Because the 2 and the x are not in parentheses, we only apply the exponent to the x. In this case, we are multiplying $\sqrt[5] (x)^{3}$ by 2.