Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 424: 52

Answer

$\dfrac{1}{a^{11/12}}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \dfrac{a^{1/4}a^{-1/2}}{a^{2/3}} \\\\= a^{\frac{1}{4}+\frac{-1}{2}-\frac{2}{3}} \\\\= a^{\frac{3}{12}-\frac{6}{12}-\frac{8}{12}} \\\\= a^{-\frac{11}{12}} \\\\= \dfrac{1}{a^{11/12}} .\end{array}
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