Answer
$\dfrac{1}{a^{11/12}}$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
\dfrac{a^{1/4}a^{-1/2}}{a^{2/3}}
\\\\=
a^{\frac{1}{4}+\frac{-1}{2}-\frac{2}{3}}
\\\\=
a^{\frac{3}{12}-\frac{6}{12}-\frac{8}{12}}
\\\\=
a^{-\frac{11}{12}}
\\\\=
\dfrac{1}{a^{11/12}}
.\end{array}