Answer
64
Work Step by Step
According to the definition of negative exponents, $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$).
Therefore, $(\frac{1}{4})^{-3}=\frac{1}{(\frac{1}{4})^{3}}=\frac{4^{3}}{1^{3}}=\frac{64}{1}=64$.
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