Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 126

Answer

$\dfrac{b^{10}}{a^{12}}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{a^{-9}b^6}{a^3b^{-4}} ,$ is equivalent to \begin{array}{l}\require{cancel} a^{-9-3}b^{6-(-4)} \\\\= a^{-9-3}b^{6+4} \\\\= a^{-12}b^{10} \\\\= \dfrac{b^{10}}{a^{12}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.