Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 95

Answer

$\frac{27}{8}$

Work Step by Step

According to the definition of negative exponents, $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$). Therefore, $(\frac{2}{3})^{-3}=\frac{1}{(\frac{2}{3})^{3}}=\frac{3^{3}}{2^{3}}=\frac{27}{8}$.
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