Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 118

Answer

$\dfrac{9}{p^{11}}$

Work Step by Step

Using the laws of exponents, the given expression, $ (3p^{-4})^2(p^3)^{-1} ,$ is equivalent to \begin{array}{l}\require{cancel} 3^2p^{-4(2)}(p^{3(-1)}) \\\\= 9p^{-8}(p^{-3}) \\\\= 9p^{-8+(-3)} \\\\= 9p^{-8-3} \\\\= 9p^{-11} \\\\= \dfrac{9}{p^{11}} .\end{array}
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