Answer
$\frac{8}{27}$
Work Step by Step
According to the definition of negative exponents, $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$).
Therefore, $(\frac{3}{2})^{-3}=\frac{1}{(\frac{3}{2})^{3}}=\frac{2^{3}}{3^{3}}=\frac{8}{27}$.
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