Answer
$\dfrac{m^{8}}{n^{11}}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{m^2n^{-8}}{m^{-6}n^3}
,$ is equivalent to
\begin{array}{l}\require{cancel}
m^{2-(-6)}n^{-8-3}
\\\\=
m^{2+6}n^{-8-3}
\\\\=
m^{8}n^{-11}
\\\\=
\dfrac{m^{8}}{n^{11}}
.\end{array}