Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 112

Answer

$\frac{1}{x^{18}}$

Work Step by Step

According to the power rule for exponents, $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are integers and $a$ is a real number). Therefore, $(x^{-3})^{6}=x^{-3\times6}=x^{-18}$. According to the negative definition for exponents, $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$). Therefore, $x^{-18}=\frac{1}{x^{18}}$.
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