Answer
$2k^{5}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{12k^{-2}(k^{-3})^{-4}}{6k^5}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{6}(2)k^{-2}(k^{-3(-4)})}{\cancel{6}k^5}
\\\\=
\dfrac{2k^{-2}(k^{12})}{k^5}
\\\\=
2k^{-2+12-5}
\\\\=
2k^{5}
.\end{array}