Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.3 Logarithmic Functions - 12.3 Exercise Set - Page 803: 104

Answer

$x=9$ or $x=\displaystyle \frac{1}{9}$

Work Step by Step

For $x\gt 0$ and $a$ a positive constant other than 1, $\log_{a}x$ is the exponent to which $a$ must be raised in order to get $x$. Thus, $\log_{a}x=m$ means $a^{m}=x$ --- The absolute brackets mean that $\left.\begin{array}{lllll} \log_{3}x=2 & & or & & \log_{3}x=-2\\ 3^{2}=x & & & & 3^{-2}=x \end{array}\right.$ $x=9$ or $x=\displaystyle \frac{1}{9}$
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