Answer
$x=5
$
Work Step by Step
Converting to exponential form, the given logarithmic equation, $
\log_2{32}=x
,$ is equivalent to
\begin{array}{l}\require{cancel}
2^x=32
\\\\
2^x=2^5=32
.\end{array}
We have now found what value x makes the above statement, $2^x=32$, true:
\begin{array}{l}\require{cancel}
x=5
.\end{array}
