Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.3 Logarithmic Functions - 12.3 Exercise Set - Page 803: 24

Answer

$0$

Work Step by Step

The logarithm of 1 to any valid base is zero. Hence, the given expression, $ \log_9 1 ,$ is equal to $ 0 .$ We can check that this is true: $9^?=1$ $9^0=1$ Because $9^0=1$, the answer that we found above is correct.
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