Answer
$\log_{16}2=\dfrac{1}{4}$
Work Step by Step
Since $b^y=x$ is equivalent to $y=\log_bx,$ the given equation, $
16^{1/4}=2
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_{16}2=\dfrac{1}{4}
.\end{array}
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