Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.3 Logarithmic Functions - 12.3 Exercise Set: 68

Answer

$\log_{2}\dfrac{1}{32}=-5$

Work Step by Step

Since $b^y=x$ is equivalent to $y=\log_bx,$ the given equation, $ 2^{-5}=\dfrac{1}{32} ,$ is equivalent to \begin{array}{l}\require{cancel} \log_{2}\dfrac{1}{32}=-5 .\end{array}
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