Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.3 Logarithmic Functions - 12.3 Exercise Set - Page 803: 43

Answer

The graph is shown below.

Work Step by Step

$f\left( x \right)={{\log }_{6}}x$ Assume, $f\left( x \right)=y$ Therefore, the function becomes, $y={{\log }_{6}}x$ Therefore, the function $y=f\left( x \right)={{\log }_{6}}x$ can be written as $x={{6}^{y}}$ Substitute $y=0,1,2,-1,-2$ in the function ${{6}^{y}}=x$ and tabulate the values as shown in Table 1. $\begin{align} & x={{6}^{0}} \\ & =1 \end{align}$ $\begin{align} & x={{6}^{1}} \\ & =6 \end{align}$ $\begin{align} & x={{6}^{2}} \\ & =36 \end{align}$ $\begin{align} & x={{6}^{-1}} \\ & =\frac{1}{6} \end{align}$ $\begin{align} & x={{6}^{-2}} \\ & =\frac{1}{36} \end{align}$ Tabulate the obtained values as shown below: $\begin{matrix} x & y \\ 1 & 0 \\ 6 & 1 \\ 36 & 2 \\ \frac{1}{6} & -1 \\ \frac{1}{36} & -2 \\ \end{matrix}$
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