Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.3 Logarithmic Functions - 12.3 Exercise Set - Page 803: 67

Answer

$-3=\displaystyle \log_{5}\frac{1}{125}$

Work Step by Step

We use the definition of logarithm to rewrite a logarithmic equation as an equivalent exponential equation or the other way around: $m=\log_{a}x$ is equivalent to $a^{m}=x.$ So, with a=5, m=-3, x=1/125, $5^{-3}=\displaystyle \frac{1}{125}$ is equivalent to $-3=\displaystyle \log_{5}\frac{1}{125}$
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