Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.3 Logarithmic Functions - 12.3 Exercise Set - Page 803: 42

Answer

The graph is shown below.

Work Step by Step

$y={{\log }_{7}}x$ Therefore, the function $y={{\log }_{7}}x$ can be written as $x={{7}^{y}}$ Substitute in a selected y value: $\begin{align} & x={{7}^{0}} \\ & =1 \end{align}$ Substitute in a selected y value: $\begin{align} & x={{7}^{1}} \\ & =7 \end{align}$ Substitute in a selected y value: $\begin{align} & x={{7}^{2}} \\ & =49 \end{align}$ Substitute in a selected y value: $\begin{align} & x={{7}^{-1}} \\ & =\frac{1}{7} \end{align}$ Substitute in a selected y value: $\begin{align} & x={{7}^{-2}} \\ & =\frac{1}{{{7}^{2}}} \\ & =\frac{1}{49} \end{align}$ Tabulate the obtained values as shown below: $\begin{matrix} x & y \\ 1 & 0 \\ 7 & 1 \\ 49 & 2 \\ \frac{1}{7} & -1 \\ \frac{1}{49} & -2 \\ \end{matrix}$
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