College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises: 58

Answer

One real solution.

Work Step by Step

We find the discriminant: $x^{2}=6x-9$ $x^{2}-6x+9=0$ $D=b^{2}-4ac=(-6)^{2}-4(1)(9)=36-36=0$ The discriminant is 0, so there is one real solution.
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