College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises: 51

Answer

$\frac{-v_0\pm\sqrt{v_0^{2}+2gh}}{g}$

Work Step by Step

$h = \displaystyle \frac{1}{2}gt^{2}+v_0t$ $\frac{1}{2}gt^{2}+v_0t-h = 0$ We use the quadratic formula: $t=\displaystyle \frac{-(v_0)\pm\sqrt{(v_0)^{2}-4(\frac{1}{2}g)(-h)}}{2(\frac{1}{2}g)}=\frac{-v_0\pm\sqrt{v_0^{2}+2gh}}{g}$
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