Answer
$x=-1$ or $x=19$
Work Step by Step
We complete the square:
$x^{2}-18x=19$
$x^{2}-18x+(-9)^{2}=19+(-9)^{2}=19+81=100$
$(x-9)^{2}=100$
$x-9=\pm\sqrt{100}=\pm 10$
$x=9\pm 10$
So we have: $x=-1$ or $x=19$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 24
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