Answer
No solution.
Work Step by Step
We use the quadratic formula:
$5x^{2}-7x+5$
$x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}=\frac{-(-7)\pm\sqrt{(-7)^{2}-4(5)(5)}}{2(5)}=\frac{7\pm\sqrt{49-100}}{10}=\frac{7\pm\sqrt{-51}}{10}$
We can't take the square root of a negative, so there are no (real) solutions.