Answer
$y=-\displaystyle \frac{7}{4}$ or $y=4$
Work Step by Step
We solve by factoring:
$4y^{2}-9y=28$
$4y^{2}-9y-28=0$
$(4y+7)(y-4)=0$
$4y+7=0$ or $y-4=0$
So we have: $y=-\displaystyle \frac{7}{4}$ or $y=4$
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